Question Number 209066 by Tawa11 last updated on 01/Jul/24
Commented by Tawa11 last updated on 01/Jul/24
Answered by A5T last updated on 01/Jul/24
$${cos}\mathrm{48}°=\frac{{XA}}{\mathrm{19}}\Rightarrow{XA}=\mathrm{19}{cos}\mathrm{48}° \\ $$$$\frac{{XA}}{{t}_{{XA}} }=\frac{{DA}}{{t}_{{DA}} }\Rightarrow{t}_{{XA}} =\frac{\mathrm{19}{cos}\mathrm{48}°×\mathrm{216}}{\mathrm{27}}\approx\mathrm{102}\:{minutes} \\ $$
Commented by Tawa11 last updated on 01/Jul/24
$$\mathrm{Thanks}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate}. \\ $$
Commented by Tawa11 last updated on 01/Jul/24
$$\mathrm{Sir},\:\mathrm{how}\:\mathrm{did}\:\mathrm{you}\:\mathrm{use}\:\mathrm{cosine}\:\mathrm{rule}. \\ $$$$\mathrm{show}\:\mathrm{me}\:\mathrm{where}\:\:\mathrm{X}\:\mathrm{is}\:\mathrm{sir}. \\ $$
Commented by Tawa11 last updated on 01/Jul/24
$$\mathrm{I}\:\mathrm{understand}\:\mathrm{now}\:\mathrm{sir}. \\ $$$$\mathrm{It}\:\mathrm{formed}\:\mathrm{right}\:\mathrm{angled}\:\mathrm{triangle} \\ $$