Question Number 209128 by Spillover last updated on 02/Jul/24
Answered by A5T last updated on 02/Jul/24
$${The}\:{length}\:{of}\:{the}\:{diagonal}\:{of}\:{the}\:{square}=\mathrm{2}{r} \\ $$$$\Rightarrow{s}^{\mathrm{2}} +{s}^{\mathrm{2}} =\mathrm{4}{r}^{\mathrm{2}} \Rightarrow\mathrm{2}{s}^{\mathrm{2}} =\mathrm{4}{r}^{\mathrm{2}} \Rightarrow{s}^{\mathrm{2}} =\mathrm{2}{r}^{\mathrm{2}} \\ $$$${r}=\mathrm{4}\Rightarrow{s}^{\mathrm{2}} =\mathrm{2}×\mathrm{16}=\mathrm{32} \\ $$
Commented by Spillover last updated on 02/Jul/24
$${thank}\:{you} \\ $$
Answered by Spillover last updated on 02/Jul/24
