Question-209129 Tinku Tara July 2, 2024 Others 0 Comments FacebookTweetPin Question Number 209129 by Adeyemi889 last updated on 02/Jul/24 Answered by A5T last updated on 02/Jul/24 x3+3x2−1=x(x2−1)+x+3x2−1=x+x+3x2−1x+3x2−1=Ax−1+Bx+1⇒x+3=(A+B)x+A−B⇒A+B=1;A−B=3⇒A=2;B=−1⇒x2+3x2−1=x+2x−1−1x+1 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Cyclic-quadrilateral-ABCD-is-inscribed-in-circle-Point-S-is-intersection-of-diagonals-AC-and-BD-S-is-not-center-of-the-circle-If-AB-BC-6-and-BS-4-what-is-length-of-BD-Next Next post: Question-209161 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.