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Question-209211




Question Number 209211 by SonGoku last updated on 03/Jul/24
Commented by A5T last updated on 03/Jul/24
AC=(√(AB^2 +BC^2 −2AB×BCcos123))≈74.738
$${AC}=\sqrt{{AB}^{\mathrm{2}} +{BC}^{\mathrm{2}} −\mathrm{2}{AB}×{BCcos}\mathrm{123}}\approx\mathrm{74}.\mathrm{738} \\ $$

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