Question Number 209358 by peter frank last updated on 08/Jul/24
![](https://www.tinkutara.com/question/34384.png)
Commented by mr W last updated on 08/Jul/24
![if the bowl is smooth, why should the small block rotate with the bowl and not fall to the middle of the bowl?](https://www.tinkutara.com/question/Q209366.png)
$${if}\:{the}\:{bowl}\:{is}\:{smooth},\:{why}\:{should}\:{the}\: \\ $$$${small}\:{block}\:{rotate}\:{with}\:{the}\:{bowl}\:{and} \\ $$$${not}\:{fall}\:{to}\:{the}\:{middle}\:{of}\:{the}\:{bowl}? \\ $$
Commented by mr W last updated on 08/Jul/24
![the answer (√((g cos θ)/R)) should be (√(g/(R cos θ)))](https://www.tinkutara.com/question/Q209375.png)
$${the}\:{answer}\:\sqrt{\frac{{g}\:\mathrm{cos}\:\theta}{{R}}}\:{should}\:{be} \\ $$$$\sqrt{\frac{{g}}{{R}\:\mathrm{cos}\:\theta}} \\ $$
Commented by mr W last updated on 08/Jul/24
![what a book are you working with? it contains too many mistakes!](https://www.tinkutara.com/question/Q209376.png)
$${what}\:{a}\:{book}\:{are}\:{you}\:{working}\:{with}? \\ $$$${it}\:{contains}\:{too}\:{many}\:{mistakes}! \\ $$
Answered by mr W last updated on 08/Jul/24
![](https://www.tinkutara.com/question/34386.png)
Commented by mr W last updated on 08/Jul/24
![mg tan θ=m(R sin θ)ω^2 ⇒ω=(√(g/(R cos θ)))](https://www.tinkutara.com/question/Q209373.png)
$${mg}\:\mathrm{tan}\:\theta={m}\left({R}\:\mathrm{sin}\:\theta\right)\omega^{\mathrm{2}} \\ $$$$\Rightarrow\omega=\sqrt{\frac{{g}}{{R}\:\mathrm{cos}\:\theta}} \\ $$
Commented by peter frank last updated on 08/Jul/24
![thank you for the solution.](https://www.tinkutara.com/question/Q209384.png)
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{for}\:\mathrm{the}\:\mathrm{solution}. \\ $$