Question-209358

Question Number 209358 by peter frank last updated on 08/Jul/24

Commented by mr W last updated on 08/Jul/24

i f t h e b o w l i s s m o o t h, w h y s h o u l d t h e

s m a l l b l o c k r o t a t e w i t h t h e b o w l a n d

n o t f a l l t o t h e m i d d l e o f t h e b o w l ?

Commented by mr W last updated on 08/Jul/24

t h e a n s w e r \sqrt{\frac{g \cos θ}{R}} s h o u l d b e

\sqrt{\frac{g}{R \cos θ}}

Commented by mr W last updated on 08/Jul/24

w h a t a b o o k a r e y o u w o r k i n g w i t h ?

i t c o n t a i n s t o o m a n y m i s t a k e s!

Answered by mr W last updated on 08/Jul/24

Commented by mr W last updated on 08/Jul/24

m g \tan θ = m (R \sin θ) ω^{2}

\Rightarrow ω = \sqrt{\frac{g}{R \cos θ}}

Commented by peter frank last updated on 08/Jul/24

thank you for the solution .