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Question Number 209434 by justenspi last updated on 10/Jul/24

H e l p

Commented by justenspi last updated on 10/Jul/24

Commented by Berbere last updated on 10/Jul/24

= \lim_{x \to a} \frac{e^{g (x)} (e^{f (x) - g (x)} - 1)}{f (x) - g (x)}

= e^{g (a)} * \lim_{x \to a} \frac{e^{h (x)} - 1}{h (x)}

x \to a h (x) \to 0

\Rightarrow e^{g (a)} . \lim_{x \to 0} \frac{e^{x} - 1}{x} = e^{a}

Commented by justenspi last updated on 10/Jul/24

T h a n k y o u S i r W i t c h e r y o u a r e t h e b e s t

Commented by justenspi last updated on 10/Jul/24

Commented by justenspi last updated on 10/Jul/24

A l s o s i r i n t h i s p r o b l e m s h o u l d n o t t h e f i n a l

a n s w e r b e a f u n c t i o n i n n

w h y d i d h e a s s u m e t h a t n = 1010