Question Number 209456 by peter frank last updated on 10/Jul/24

Answered by Ghisom last updated on 10/Jul/24

Commented by peter frank last updated on 11/Jul/24

Answered by Spillover last updated on 10/Jul/24

Then
TanA=opposite/adjacent
Tan A=√s/r
Also
Tan B=opp/adj
=r/√s
By considering angle B
adjacent=√s
Opposite =r
from a²+b²=c²
r²+(√s)²=c²
c²=r²+s
c=√(r²+s)
Hyp=√(r²+s)
Now
Cos B=adj/hyp
Cos B=√s/√(r²+s)
We know that
√x/√y=√(x/y)
Hence
√s/√(r²+s)=√(s/r²+s)
Therefore :CosB=√(s/r²+s)
Commented by Spillover last updated on 10/Jul/24
