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Question-209458




Question Number 209458 by SonGoku last updated on 10/Jul/24
Commented by SonGoku last updated on 10/Jul/24
l = ?   BC =  l + 200m  BA^� C = 120°  AB^� C = 38°12′48′′
l=?BC=l+200mBAC^=120°ABC^=38°1248
Commented by mr W last updated on 10/Jul/24
((BC)/(sin ∠BAC))=((AC)/(sin ∠ABC))  ((l+200)/(sin 120°))=(l/(sin 38°12′48′′))  l=((200)/(((√3)/(2 sin 38°12′48′′))−1))=500 m
BCsinBAC=ACsinABCl+200sin120°=lsin38°1248l=20032sin38°12481=500m
Commented by SonGoku last updated on 10/Jul/24
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