Question-209458

Question Number 209458 by SonGoku last updated on 10/Jul/24

Commented by SonGoku last updated on 10/Jul/24

l = ?

BC = l + 200 m

B \hat{A C} = 120 °

A \hat{B C} = 38 ° 12^{'} 48^{″}

Commented by mr W last updated on 10/Jul/24

\frac{B C}{\sin ∠ B A C} = \frac{A C}{\sin ∠ A B C}

\frac{l + 200}{\sin 120 °} = \frac{l}{\sin 38 ° 12^{'} 48^{″}}

l = \frac{200}{\frac{\sqrt{3}}{2 \sin 38 ° 12^{'} 48^{″}} - 1} = 500 m

Commented by SonGoku last updated on 10/Jul/24

Thank you

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