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Question-209465




Question Number 209465 by RoseAli last updated on 10/Jul/24
Answered by mr W last updated on 10/Jul/24
x−2=0 ⇒x=2  x−2=±1 ⇒x=1 or 3  10x^2 −1=3x ⇒(2x−1)(5x+1)=0 ⇒x=−(1/5) or (1/2)  ⇒5 solutions
$${x}−\mathrm{2}=\mathrm{0}\:\Rightarrow{x}=\mathrm{2} \\ $$$${x}−\mathrm{2}=\pm\mathrm{1}\:\Rightarrow{x}=\mathrm{1}\:{or}\:\mathrm{3} \\ $$$$\mathrm{10}{x}^{\mathrm{2}} −\mathrm{1}=\mathrm{3}{x}\:\Rightarrow\left(\mathrm{2}{x}−\mathrm{1}\right)\left(\mathrm{5}{x}+\mathrm{1}\right)=\mathrm{0}\:\Rightarrow{x}=−\frac{\mathrm{1}}{\mathrm{5}}\:{or}\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow\mathrm{5}\:{solutions} \\ $$

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