Question Number 209495 by Tawa11 last updated on 11/Jul/24
Commented by Tawa11 last updated on 11/Jul/24
$$\mathrm{Find}\:\mathrm{the}\:\mathrm{missing}\:\mathrm{angle}\:\left(\mathrm{the}\:\mathrm{red}\right) \\ $$
Answered by mr W last updated on 11/Jul/24
Commented by mr W last updated on 11/Jul/24
$$\mathrm{34}+\alpha+\mathrm{15}+\alpha=\mathrm{180} \\ $$$$\Rightarrow\alpha=\frac{\mathrm{180}−\mathrm{34}−\mathrm{15}}{\mathrm{2}}=\mathrm{65}.\mathrm{5}° \\ $$$$\beta=\alpha+\mathrm{15}=\mathrm{65}.\mathrm{5}+\mathrm{15}=\mathrm{80}.\mathrm{5}° \\ $$
Commented by Tawa11 last updated on 11/Jul/24
$$\mathrm{Wow},\:\mathrm{great}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}.\:\mathrm{My}\:\mathrm{steps}\:\mathrm{is}\:\mathrm{very}\:\mathrm{long}. \\ $$
Commented by Tawa11 last updated on 11/Jul/24
$$\mathrm{Sir},\:\:\mathrm{why}\:\mathrm{is}\:\:\:\:\:\alpha\:\:+\:\:\alpha\:\:+\:\:\mathrm{15}\:\:\:\mathrm{not}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{180}?? \\ $$$$\mathrm{It}\:\mathrm{look}\:\mathrm{like}\:\mathrm{angle}\:\mathrm{on}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{line}. \\ $$
Commented by Tawa11 last updated on 11/Jul/24
$$\mathrm{But}\:\mathrm{I}\:\mathrm{understand}\:\mathrm{your}\:\mathrm{workings}\:\mathrm{perfectly}\:\mathrm{sir}. \\ $$$$\mathrm{Am}\:\mathrm{only}\:\mathrm{asking}\:\mathrm{that}\:\mathrm{because}\:\mathrm{it}\:\mathrm{look}\:\mathrm{like}\:\mathrm{straight}\:\mathrm{line}. \\ $$
Commented by mr W last updated on 11/Jul/24
$${it}\:{is}\:\alpha+\mathrm{15}+\boldsymbol{\gamma}=\mathrm{180}°\:!! \\ $$$${and}\:\gamma\neq\alpha \\ $$
Commented by Tawa11 last updated on 11/Jul/24
$$\mathrm{I}\:\mathrm{grab}\:\mathrm{sir}. \\ $$