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I-0-0-1-1-x-2-y-2-x-2-y-2-dxdy-using-polar-system-




Question Number 209624 by mnjuly1970 last updated on 16/Jul/24
    I=∫_0 ^( ∞) ∫_0 ^( ∞)  (( 1)/(1+ x^2  +y^2  +x^2 y^2 )) dxdy=?   using    polar  system...
I=0011+x2+y2+x2y2dxdy=?usingpolarsystem
Answered by mr W last updated on 16/Jul/24
=∫_0 ^∞ ∫_0 ^∞ (1/((1+x^2 )(1+y^2 )))dxdy  =[∫_0 ^∞ (1/(1+x^2 ))dx]^2   =([tan^(−1) x]_0 ^∞ )^2   =((π/2))^2 =(π^2 /4)
=001(1+x2)(1+y2)dxdy=[011+x2dx]2=([tan1x]0)2=(π2)2=π24

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