Question-209633 Tinku Tara July 17, 2024 Algebra 0 Comments FacebookTweetPin Question Number 209633 by Abdullahrussell last updated on 17/Jul/24 Answered by som(math1967) last updated on 17/Jul/24 (x+1)(3x+2)(6x+5)2=6⇒(3x2+5x+2)(36x2+60x+25)=6⇒(a+2)(12a+25)=6[let3x2+5x=a]⇒12a2+49a+50−6=0⇒12a2+49a+44=0⇒12a2+16a+33a+44=0⇒4a(3a+4)+11(3a+4)=0⇒(3a+4)(4a+11)=0(9x2+15x+4)(12x2+20x+11)=0if(9x2+15x+4)=0(3x)2+2.3x.52+254=254−4∴(3x+52)2=94 Answered by MM42 last updated on 17/Jul/24 16[(6x+5)+1)12[(6x+5)−1)(6x+5)2=6(u+1)(u−1)(u)2=72(u2−1)u2−72=u4−u2−72=0(u2−9)(u2+8)=0u=±3&u=±22i(3x+52)2=14(6x+5)2=94✓&−2✓ Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: if-the-acceleration-is-constant-what-will-be-the-average-and-instantaneous-accelerations-Next Next post: Question-209639 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.