Question-209718

Question Number 209718 by Ismoiljon_008 last updated on 19/Jul/24

Answered by mr W last updated on 19/Jul/24

a_{n} = \frac{1}{n! \times (n + 2)} = \frac{1}{(n + 1)!} - \frac{1}{(n + 2)!}

\underset{n = 1}{\sum^{2023}} a_{n} = (\frac{1}{2!} - \frac{1}{3!}) + (\frac{1}{3!} - \frac{1}{4!}) + \dots + (\frac{1}{2024!} - \frac{1}{2025!}

= \frac{1}{2} - \frac{1}{2025!} \Rightarrow C)

Commented by Ismoiljon_008 last updated on 19/Jul/24

t h a n k y o u M r W

I a p p r e c i a t e y o u