Magnitude-A-varies-proportionally-with-B-squared-4-and-magnitude-B-varies-proportionally-with-the-root-of-C-5-Also-when-A-is-16-B-is-12-and-C-takes-the-value-81-Calculate-the-value-that-A

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Question Number 209860 by lmcp1203 last updated on 23/Jul/24

$$$$$$\mathrm{Magnitude}\mathrm{A}\mathrm{varies}\mathrm{proportionally}\mathrm{with}(\mathrm{B}\mathrm{squared}+4)\mathrm{and}\mathrm{magnitude}\mathrm{B}\mathrm{varies}\mathrm{proportionally}\mathrm{with}$$$$\left(t\mathrm{he}\mathrm{root}\mathrm{of}\mathrm{C}\right)-5.\mathrm{Also}\mathrm{when}\mathrm{A}\mathrm{is}16,\mathrm{B}\mathrm{is}12\mathrm{and}\mathrm{C}\mathrm{takes}\mathrm{the}\mathrm{value}81.\mathrm{Calculate}\mathrm{the}\mathrm{value}\mathrm{that}\mathrm{A}\mathrm{takes}$$$$\mathrm{wh}e\mathrm{n}\mathrm{C}\mathrm{is}49.helpme.please.thanks$$

Answered by mr W last updated on 23/Jul/24

$$A=\alpha (B^2-4)$$$$B=\beta (\sqrt{C}-5)$$$$16=\alpha ({12}^2-4)\Rightarrow \alpha =\frac{4}{35}$$$$12=\beta (\sqrt{81}-5)\Rightarrow \beta =3$$$$whenC=49:$$$$B=3\times (\sqrt{49}-5)=6$$$$A=\frac{4}{35}(6^2-4)=\frac{128}{35}\leftarrow answer$$

Answered by lmcp1203 last updated on 23/Jul/24

$$thankyou.$$

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