Question Number 209957 by Jubr last updated on 26/Jul/24
If x, y are contain in natural numbers
and
x² + y² = 613²
Find the values of x + y = ?
and
x² + y² = 613²
Find the values of x + y = ?
Answered by Frix last updated on 27/Jul/24
$$\mathrm{35}^{\mathrm{2}} +\mathrm{612}^{\mathrm{2}} =\mathrm{613}^{\mathrm{2}} \:\:\:\:\:{x}+{y}=\mathrm{647} \\ $$$$\mathrm{0}^{\mathrm{2}} +\mathrm{613}^{\mathrm{2}} =\mathrm{613}^{\mathrm{2}} \:\:\:\:\:\:\:\:{x}+{y}=\mathrm{613} \\ $$
Commented by Jubr last updated on 28/Jul/24
$${Thanks}\:{sir} \\ $$