Question Number 209965 by mnjuly1970 last updated on 27/Jul/24
Answered by mr W last updated on 27/Jul/24
Commented by mr W last updated on 27/Jul/24
$$\frac{{AD}}{{DB}}=\frac{{AD}}{{FH}}=\frac{\mathrm{1}}{\mathrm{2}}\:\Rightarrow\frac{{AD}}{{AB}}=\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\frac{{AE}}{{AC}}=\frac{{AD}}{{FG}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\frac{\Delta{ADE}}{\Delta{ABC}}=\frac{{AE}×{AD}}{{AC}×{AB}}=\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{1}}{\mathrm{3}}=\frac{\mathrm{1}}{\mathrm{6}} \\ $$
Commented by mnjuly1970 last updated on 27/Jul/24
$${thx}\:{alot}\:{sir} \\ $$