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calcul-0-1-nt-n-1-1-t-t-n-dt-




Question Number 210133 by SANOGO last updated on 31/Jul/24
calcul  ∫_0 ^1 [nt^(n−1) (1−t)−t^n ]dt
$${calcul} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \left[{nt}^{{n}−\mathrm{1}} \left(\mathrm{1}−{t}\right)−{t}^{{n}} \right]{dt} \\ $$
Answered by mr W last updated on 01/Aug/24
=∫_0 ^1 (nt^(n−1) −(n+1)t^n )dt  =[t^n −t^(n+1) ]_0 ^1   =1^n −1^(n+1)   =0
$$=\int_{\mathrm{0}} ^{\mathrm{1}} \left({nt}^{{n}−\mathrm{1}} −\left({n}+\mathrm{1}\right){t}^{{n}} \right){dt} \\ $$$$=\left[{t}^{{n}} −{t}^{{n}+\mathrm{1}} \right]_{\mathrm{0}} ^{\mathrm{1}} \\ $$$$=\mathrm{1}^{{n}} −\mathrm{1}^{{n}+\mathrm{1}} \\ $$$$=\mathrm{0} \\ $$

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