Question Number 210292 by 281981 last updated on 05/Aug/24
Commented by mr W last updated on 05/Aug/24
$${all}\:{answers}\:{are}\:{wrong}! \\ $$
Answered by mr W last updated on 05/Aug/24
![((x−α)/3)=((y−(2α−1))/(−2))=((−2[3α−2(2α−1)+4])/(3^2 +(−2)^2 )) ⇒13x=19α−36 ⇒13y=22α+11 ⇒19y−22x=77](https://www.tinkutara.com/question/Q210304.png)
$$\frac{{x}−\alpha}{\mathrm{3}}=\frac{{y}−\left(\mathrm{2}\alpha−\mathrm{1}\right)}{−\mathrm{2}}=\frac{−\mathrm{2}\left[\mathrm{3}\alpha−\mathrm{2}\left(\mathrm{2}\alpha−\mathrm{1}\right)+\mathrm{4}\right]}{\mathrm{3}^{\mathrm{2}} +\left(−\mathrm{2}\right)^{\mathrm{2}} } \\ $$$$\Rightarrow\mathrm{13}{x}=\mathrm{19}\alpha−\mathrm{36} \\ $$$$\Rightarrow\mathrm{13}{y}=\mathrm{22}\alpha+\mathrm{11} \\ $$$$ \\ $$$$\Rightarrow\mathrm{19}{y}−\mathrm{22}{x}=\mathrm{77} \\ $$
Commented by mr W last updated on 05/Aug/24
