Question-210607

Question Number 210607 by peter frank last updated on 13/Aug/24

Answered by A5T last updated on 14/Aug/24

75 (5^{3 {l o g}_{2} x}) = 75 {(2^{{l o g}_{2} 5})}^{{l o g}_{2} x \times 3} = 75 {(2^{{l o g}_{2} x})}^{3 {l o g}_{2} 5}

= 75 {(x)}^{3 {l o g}_{2} 5} = 4 x

\Rightarrow x^{{l o g}_{2} (\frac{125}{2})} = \frac{4}{75} \Rightarrow x = {(\frac{4}{75})}^{\frac{1}{{l o g}_{2} (125) - 1}} \approx 0.6118

Commented by peter frank last updated on 14/Aug/24

Commented by peter frank last updated on 14/Aug/24

where did that 2 come from ?

Commented by A5T last updated on 14/Aug/24

b = a^{{l o g}_{a} b} \Rightarrow 5 = 2^{{l o g}_{2} 5}

Answered by Spillover last updated on 14/Aug/24

Answered by Spillover last updated on 14/Aug/24