Question Number 210689 by Tawa11 last updated on 16/Aug/24
Answered by mm1342 last updated on 16/Aug/24
$${AM}={MD}={a}\Rightarrow{BC}=\frac{\mathrm{2}}{\mathrm{3}}{a} \\ $$$$\frac{{s}}{{S}}=\frac{\frac{{BC}×{h}}{\mathrm{2}}}{\frac{\left({BC}+{AD}\right){h}}{\mathrm{2}}}=\frac{{BC}}{{BC}+{AD}}=\frac{\frac{\mathrm{2}}{\mathrm{3}}{a}}{\mathrm{2}{a}+\frac{\mathrm{2}}{\mathrm{3}}{a}} \\ $$$$=\frac{\mathrm{1}}{\mathrm{4}}\:\checkmark \\ $$$$ \\ $$
Commented by Tawa11 last updated on 16/Aug/24
$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{appreciate}. \\ $$