Question-210786 Tinku Tara August 19, 2024 Differential Equation 0 Comments FacebookTweetPin Question Number 210786 by zhou0429 last updated on 19/Aug/24 Answered by Berbere last updated on 19/Aug/24 x9+1=∏8k=0(x−eiπ(1+2k9))=p(x)=Σ∫1(x−eiπ(1+2k9))p′(eiπ(1+2k9))dx=∑∞k=0ln(x−eiπ(1+2k9))P′(eiπ(1+2k9))+c Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: If-D-x-2-y-2-z-2-1-D-x-2-2y-2-x-2-4y-2-z-2-dxdydz-Next Next post: Question-210816 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.