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8x-2-13x-11-2-x-1-3-x-3x-2-2-1-3-x-




Question Number 210870 by hardmath last updated on 20/Aug/24
8x^2  − 13x + 11 = (2/x) + (1 + (3/x)) ((3x^2 −2))^(1/3)   x = ?
$$\mathrm{8x}^{\mathrm{2}} \:−\:\mathrm{13x}\:+\:\mathrm{11}\:=\:\frac{\mathrm{2}}{\mathrm{x}}\:+\:\left(\mathrm{1}\:+\:\frac{\mathrm{3}}{\mathrm{x}}\right)\:\sqrt[{\mathrm{3}}]{\mathrm{3x}^{\mathrm{2}} −\mathrm{2}} \\ $$$$\boldsymbol{\mathrm{x}}\:=\:? \\ $$
Commented by Ghisom last updated on 20/Aug/24
obviously x=1
$$\mathrm{obviously}\:{x}=\mathrm{1} \\ $$

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