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Question-210971

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Question Number 210971 by black_mamba234 last updated on 25/Aug/24
Answered by A5T last updated on 25/Aug/24
2) 2x_1 +4y_1 −2z_1 =2(x_1 +k)+4y_1 −2(z_1 +k) f(x_1 ,y_1 ,z_1 )=f(x_2 ,y_2 ,z_2 )⇏(x_1 ,y_1 ,z_1 )=(x_2 ,y_2 ,z_2 ) ⇒ f is not injective.
2)2x1+4y1−2z1=2(x1+k)+4y1−2(z1+k)f(x1,y1,z1)=f(x2,y2,z2)⇏(x1,y1,z1)=(x2,y2,z2)⇒fisnotinjective.

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