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Question-210987




Question Number 210987 by RojaTaniya last updated on 25/Aug/24
Answered by Frix last updated on 25/Aug/24
x^6 −((133)/(78))x^5 +((133)/(78))x−1=0  (x−1)(x+1)(x−(2/3))(x−(3/2))(x^2 +(6/(13))x+1)=0
$${x}^{\mathrm{6}} −\frac{\mathrm{133}}{\mathrm{78}}{x}^{\mathrm{5}} +\frac{\mathrm{133}}{\mathrm{78}}{x}−\mathrm{1}=\mathrm{0} \\ $$$$\left({x}−\mathrm{1}\right)\left({x}+\mathrm{1}\right)\left({x}−\frac{\mathrm{2}}{\mathrm{3}}\right)\left({x}−\frac{\mathrm{3}}{\mathrm{2}}\right)\left({x}^{\mathrm{2}} +\frac{\mathrm{6}}{\mathrm{13}}{x}+\mathrm{1}\right)=\mathrm{0} \\ $$

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