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Question-211001




Question Number 211001 by lmcp1203 last updated on 26/Aug/24
Commented by mr W last updated on 26/Aug/24
is the “inclined plane” just a wedge  which can slide frictionlessly on the  ground? or the wedge is fixed with  the ground?
$${is}\:{the}\:“{inclined}\:{plane}''\:{just}\:{a}\:{wedge} \\ $$$${which}\:{can}\:{slide}\:{frictionlessly}\:{on}\:{the} \\ $$$${ground}?\:{or}\:{the}\:{wedge}\:{is}\:{fixed}\:{with} \\ $$$${the}\:{ground}? \\ $$
Commented by lmcp1203 last updated on 27/Aug/24
is fixed .
$${is}\:{fixed}\:. \\ $$
Commented by mr W last updated on 27/Aug/24
in second case:  weighing machines displays mgcos θ.  thefirst case is not clearly defined.
$${in}\:{second}\:{case}: \\ $$$${weighing}\:{machines}\:{displays}\:{mg}\mathrm{cos}\:\theta. \\ $$$${thefirst}\:{case}\:{is}\:{not}\:{clearly}\:{defined}. \\ $$
Commented by lmcp1203 last updated on 28/Aug/24
thanks.  in the first case for the lecture to be mgcos(tetha) what should be corrected?
$${thanks}. \\ $$$${in}\:{the}\:{first}\:{case}\:{for}\:{the}\:{lecture}\:{to}\:{be}\:{mgcos}\left({tetha}\right)\:{what}\:{should}\:{be}\:{corrected}? \\ $$
Commented by lmcp1203 last updated on 28/Aug/24

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