Menu Close

Question-211079




Question Number 211079 by Ari last updated on 27/Aug/24
Answered by A5T last updated on 27/Aug/24
Suppose DB⊥AC  A_2 =((DB×AB)/2)=63;A_1 =((EA×AB)/2)=144  (A_2 /A_1 )=((63)/(144))=((DB)/(EA))=(7/(16))⇒(A_3 /(A_1 +A_2 +A_3 ))=((7/(16)))^2   ⇒A_3 =49u^2
SupposeDBACA2=DB×AB2=63;A1=EA×AB2=144A2A1=63144=DBEA=716A3A1+A2+A3=(716)2A3=49u2
Commented by Ari last updated on 27/Aug/24
but DB is not given perpendicular to AC
butDBisnotgivenperpendiculartoAC
Commented by A5T last updated on 27/Aug/24
Then it cannot be unique or it won′t be   dependent on it being perpendicular
Thenitcannotbeuniqueoritwontbedependentonitbeingperpendicular
Commented by Ari last updated on 27/Aug/24
Ok,you are right !
Ok,youareright!
Commented by mm1342 last updated on 27/Aug/24
if   △_1 ≈ △_2  ⇒ (s_1 /s_2 )=k^2   ⇒(A_3 /(A_1 +A_2 +A_3 ))=(((DB)/(EA)))^2 =((49)/(256))  ⇒A_3 =49 ✓
if12s1s2=k2A3A1+A2+A3=(DBEA)2=49256A3=49

Leave a Reply

Your email address will not be published. Required fields are marked *