sin-sin-find-and-

Question Number 211075 by ajfour last updated on 27/Aug/24

\sin (θ + ϕ) = θ

\sin θ = ϕ

f i n d θ a n d ϕ .

Answered by Ghisom last updated on 27/Aug/24

we can only approximate

ϕ = \sin θ

\sin (θ + \sin θ) = θ

1 . θ = ϕ = 0

2 . θ \approx \pm . 973696169714 \land ϕ \approx \pm . 826969516935

Answered by ajfour last updated on 27/Aug/24

\cos (θ + ϕ) = \sqrt{1 - θ^{2}}

\tan (θ + ϕ) = \frac{θ}{\sqrt{1 - θ^{2}}}

\frac{\tan θ + \tan ϕ}{1 - \tan θ \tan ϕ} = \frac{θ}{\sqrt{1 - θ^{2}}}

\tan ϕ = \frac{θ - \sqrt{1 - θ^{2}} \tan θ}{\sqrt{1 - θ^{2}} + θ \tan θ}

\dots y e s s o b i t

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