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Question-211143




Question Number 211143 by boblosh last updated on 29/Aug/24
Answered by A5T last updated on 29/Aug/24
Let width be w⇒w=y+12  perimeter=2(w+y)  2(w+30+y+30)=3×2(w+y)  ⇒w+y=30⇒y+12+y=30⇒y=9  ⇒length=9 and width=21
$${Let}\:{width}\:{be}\:{w}\Rightarrow{w}={y}+\mathrm{12} \\ $$$${perimeter}=\mathrm{2}\left({w}+{y}\right) \\ $$$$\mathrm{2}\left({w}+\mathrm{30}+{y}+\mathrm{30}\right)=\mathrm{3}×\mathrm{2}\left({w}+{y}\right) \\ $$$$\Rightarrow{w}+{y}=\mathrm{30}\Rightarrow{y}+\mathrm{12}+{y}=\mathrm{30}\Rightarrow{y}=\mathrm{9} \\ $$$$\Rightarrow{length}=\mathrm{9}\:{and}\:{width}=\mathrm{21} \\ $$

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