Question-211402

Question Number 211402 by efronzo1 last updated on 08/Sep/24

Answered by A5T last updated on 08/Sep/24

Q 211029, w e c a n f i n d a p o l y n o m i a l f (x)

f (x) = x^{n} \underline{+} 1

f (3) = 28 \Rightarrow f (x) = x^{3} + 1

(x^{3} + 1) (\frac{1}{x^{3}} + 1) = (x^{3} + 1) + (\frac{1}{x^{3}} + 1)

\Rightarrow f (- 2) + f (- \frac{1}{2}) = - (6 \frac{1}{8}) = - \frac{49}{8}

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