Question Number 211419 by maryaaaa last updated on 08/Sep/24
Answered by mahdipoor last updated on 08/Sep/24
![salam :) f(x)=x^2 −2[x] , f(−((f((√3)))/2))=? f((√3))=((√3))^2 −2[(√3)]=3−2×1=1 f(−(1/2))=(−0.5)^2 −2[−0.5]=0.25−2×−1=2.25](https://www.tinkutara.com/question/Q211423.png)
$$\left.{salam}\:\::\right) \\ $$$${f}\left({x}\right)={x}^{\mathrm{2}} −\mathrm{2}\left[{x}\right]\:\:\:,\:\:\:{f}\left(−\frac{{f}\left(\sqrt{\mathrm{3}}\right)}{\mathrm{2}}\right)=? \\ $$$${f}\left(\sqrt{\mathrm{3}}\right)=\left(\sqrt{\mathrm{3}}\right)^{\mathrm{2}} −\mathrm{2}\left[\sqrt{\mathrm{3}}\right]=\mathrm{3}−\mathrm{2}×\mathrm{1}=\mathrm{1} \\ $$$${f}\left(−\frac{\mathrm{1}}{\mathrm{2}}\right)=\left(−\mathrm{0}.\mathrm{5}\right)^{\mathrm{2}} −\mathrm{2}\left[−\mathrm{0}.\mathrm{5}\right]=\mathrm{0}.\mathrm{25}−\mathrm{2}×−\mathrm{1}=\mathrm{2}.\mathrm{25} \\ $$