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Question Number 211513 by Davidtim last updated on 11/Sep/24
why we use Ampier meter sequence  with resistance in circuit?
$${why}\:{we}\:{use}\:{Ampier}\:{meter}\:{sequence} \\ $$$${with}\:{resistance}\:{in}\:{circuit}? \\ $$
Commented by Frix last updated on 11/Sep/24
Because  Ohm=((Volt)/(Ampere))  ⇔  Volt=Ampere×Ohm  ⇔  Ampere=((Volt)/(Ohm))  If you have low to no resistance the current  becomes very high and you′ll end with an  electrical short. Your meter will blow.
$$\mathrm{Because} \\ $$$$\mathrm{Ohm}=\frac{\mathrm{Volt}}{\mathrm{Ampere}} \\ $$$$\Leftrightarrow \\ $$$$\mathrm{Volt}=\mathrm{Ampere}×\mathrm{Ohm} \\ $$$$\Leftrightarrow \\ $$$$\mathrm{Ampere}=\frac{\mathrm{Volt}}{\mathrm{Ohm}} \\ $$$$\mathrm{If}\:\mathrm{you}\:\mathrm{have}\:\mathrm{low}\:\mathrm{to}\:\mathrm{no}\:\mathrm{resistance}\:\mathrm{the}\:\mathrm{current} \\ $$$$\mathrm{becomes}\:\mathrm{very}\:\mathrm{high}\:\mathrm{and}\:\mathrm{you}'\mathrm{ll}\:\mathrm{end}\:\mathrm{with}\:\mathrm{an} \\ $$$$\mathrm{electrical}\:\mathrm{short}.\:\mathrm{Your}\:\mathrm{meter}\:\mathrm{will}\:\mathrm{blow}. \\ $$

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