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Question-211634




Question Number 211634 by BaliramKumar last updated on 15/Sep/24
Answered by golsendro last updated on 15/Sep/24
 x^3 +(1/x^3 ) = ((64+1)/8) = 2^3 +(1/2^3 )   y^3 +(1/y^3 ) = ((729+1)/(27))= 3^3 +(1/3^3 )    xy = 6
$$\:\mathrm{x}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{3}} }\:=\:\frac{\mathrm{64}+\mathrm{1}}{\mathrm{8}}\:=\:\mathrm{2}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{3}} } \\ $$$$\:\mathrm{y}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{y}^{\mathrm{3}} }\:=\:\frac{\mathrm{729}+\mathrm{1}}{\mathrm{27}}=\:\mathrm{3}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{3}} } \\ $$$$\:\:\mathrm{xy}\:=\:\mathrm{6} \\ $$
Commented by BaliramKumar last updated on 15/Sep/24
thanks
$${thanks} \\ $$

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