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Question-211635




Question Number 211635 by BaliramKumar last updated on 15/Sep/24
Answered by golsendro last updated on 15/Sep/24
 10^(31) −5−10^(30) −p=10^(30) (10−1)−(5+p)   9.10^3 −(5+p) divisible by 3   so p=1 , 4 , 7
$$\:\mathrm{10}^{\mathrm{31}} −\mathrm{5}−\mathrm{10}^{\mathrm{30}} −\mathrm{p}=\mathrm{10}^{\mathrm{30}} \left(\mathrm{10}−\mathrm{1}\right)−\left(\mathrm{5}+\mathrm{p}\right) \\ $$$$\:\mathrm{9}.\mathrm{10}^{\mathrm{3}} −\left(\mathrm{5}+\mathrm{p}\right)\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{3} \\ $$$$\:\mathrm{so}\:\mathrm{p}=\mathrm{1}\:,\:\mathrm{4}\:,\:\mathrm{7}\: \\ $$

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