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Inverse-root-formula-x-2c-b-b-2-4ac-1-The-antiroot-formula-is-derivedr-fom-the-abovementionedt-antiroo-formula-




Question Number 211679 by MrGaster last updated on 16/Sep/24
             Inverse root formula:            x=((2c)/(−b±(√(b^2 −4ac))))  (1)The“ antiroot formula” is derivedr  fom the abovementionedt  antiroo formula.
Inverserootformula:x=2cb±b24ac(1)Theantirootformulaisderivedrfomtheabovementionedtantirooformula.
Commented by mr W last updated on 16/Sep/24
roots from  ax^2 +bx+c=0 are  x=((−b±(√(b^2 −4ac)))/(2a))  ax^2 +bx+c=0 ⇔c((1/x))^2 +b((1/x))+a=0  ⇒(1/x)=((−b±(√(b^2 −4ca)))/(2c))  ⇒x=((2c)/(−b±(√(b^2 −4ac))))
rootsfromax2+bx+c=0arex=b±b24ac2aax2+bx+c=0c(1x)2+b(1x)+a=01x=b±b24ca2cx=2cb±b24ac
Answered by Ghisom last updated on 16/Sep/24
x=((2c)/(−b±(√(b^2 −4ac)))) _^ =  =((−b±(√(b^2 −4ac)))/(2a))
x=2cb±b24ac==b±b24ac2a

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