ax-2-bx-c-0-has-roots-and-and-show-that-b-2-ac-2- Tinku Tara September 21, 2024 Logarithms 0 Comments FacebookTweetPin Question Number 211815 by alcohol last updated on 21/Sep/24 ax2+bx+c=0hasrootsαandβandαβ=λμ.showthatλμb2=ac(λ+μ)2 Answered by som(math1967) last updated on 22/Sep/24 letα=kλ,β=kμk(λ+μ)=−ba⇒k2(λ+μ)2=b2a2k2=b2a2(λ+μ)2againk2λμ=ca⇒b2λμa2(λ+μ)2=ca∴λμb2=ac(λ+μ)2 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-211788Next Next post: Question-211796 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.