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Question Number 211861 by hardmath last updated on 22/Sep/24
ab^(−) + ba^(−) = 4c a + b + 3c = ?
ab―+ba―=4ca+b+3c=?
Answered by A5T last updated on 22/Sep/24
10a+b+10b+a=11(a+b)=4c a+b=4k≤9+9=18⇒k≤4 ⇒44k=4c⇒c=11k≤44⇒c∈(11,22,33,44) when c=11; a+b=4⇒a+b+3c=37 when c=22; a+b=8⇒a+b+3c=74 when c=33; a+b=12⇒a+b+3c=111 when c=44; a+b=16⇒a+b+3c=148
10a+b+10b+a=11(a+b)=4ca+b=4k⩽9+9=18⇒k⩽4⇒44k=4c⇒c=11k⩽44⇒c∈(11,22,33,44)whenc=11;a+b=4⇒a+b+3c=37whenc=22;a+b=8⇒a+b+3c=74whenc=33;a+b=12⇒a+b+3c=111whenc=44;a+b=16⇒a+b+3c=148

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