Question-211956

Question Number 211956 by Durganand last updated on 25/Sep/24

Answered by Frix last updated on 25/Sep/24

\tan α = t \tan 2 α = \frac{2 t}{1 - t^{2}} \sin 2 α = \frac{2 t}{1 + t^{2}}

\frac{1}{t} - \frac{1 - t^{2}}{2 t} = \frac{2 - (1 - t^{2})}{2 t} = \frac{1 + t^{2}}{2 t} = \frac{1}{\sin 2 α}

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