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Question-212083




Question Number 212083 by Spillover last updated on 28/Sep/24
Answered by Frix last updated on 28/Sep/24
I=∫ ((cos x +sin x −1)/2)dx=  =−((x+cos x −sin x)/2)+C
$${I}=\int\:\frac{\mathrm{cos}\:{x}\:+\mathrm{sin}\:{x}\:−\mathrm{1}}{\mathrm{2}}{dx}= \\ $$$$=−\frac{{x}+\mathrm{cos}\:{x}\:−\mathrm{sin}\:{x}}{\mathrm{2}}+{C} \\ $$
Commented by Spillover last updated on 06/Oct/24
great
$${great} \\ $$

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