find-the-last-two-digits-of-9-9-9-

Question Number 212201 by universe last updated on 06/Oct/24

find the last two digits of 9^{9^{9}} ?

Answered by A5T last updated on 06/Oct/24

9^{9} = {(81)}^{4} \times 9 \equiv 9 (m o d 40)

\Rightarrow 9^{9^{9}} \equiv 9^{9} = {(729)}^{3} \equiv 29^{3} \equiv 89 (m o d 100)

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