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ax-2-bx-c-0-a-b-c-and-two-roots-of-the-eqn-are-5-consecutive-integers-in-some-order-Find-their-values-




Question Number 212354 by RojaTaniya last updated on 11/Oct/24
  ax^2 +bx+c=0   a,b,c and two roots of the eqn.   are 5 consecutive integers in    some order. Find their values.
$$\:\:{ax}^{\mathrm{2}} +{bx}+{c}=\mathrm{0} \\ $$$$\:{a},{b},{c}\:{and}\:{two}\:{roots}\:{of}\:{the}\:{eqn}. \\ $$$$\:{are}\:\mathrm{5}\:{consecutive}\:{integers}\:{in}\: \\ $$$$\:{some}\:{order}.\:{Find}\:{their}\:{values}. \\ $$
Commented by Ghisom last updated on 12/Oct/24
ax^2 +bx+c=a(x−p)(x−q)  c=−2  p=−1  b=0  q=1  a=2
$${ax}^{\mathrm{2}} +{bx}+{c}={a}\left({x}−{p}\right)\left({x}−{q}\right) \\ $$$${c}=−\mathrm{2} \\ $$$${p}=−\mathrm{1} \\ $$$${b}=\mathrm{0} \\ $$$${q}=\mathrm{1} \\ $$$${a}=\mathrm{2} \\ $$

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