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AB-BC-CD-DE-in-pentagon-ABCDE-angle-B-96-o-and-angle-C-and-angle-D-108-o-Then-find-angle-A-Help-me-please-




Question Number 212383 by Ismoiljon_008 last updated on 12/Oct/24
     AB=BC=CD=DE  in pentagon ABCDE,     angle B=96^o  and angle C and angle      D=108^o . Then find angle A     Help me please
$$ \\ $$$$\:\:\:{AB}={BC}={CD}={DE}\:\:{in}\:{pentagon}\:{ABCDE}, \\ $$$$\:\:\:{angle}\:{B}=\mathrm{96}^{{o}} \:{and}\:{angle}\:{C}\:{and}\:{angle}\: \\ $$$$\:\:\:{D}=\mathrm{108}^{{o}} .\:{Then}\:{find}\:{angle}\:{A} \\ $$$$\:\:\:\mathbb{H}{elp}\:{me}\:{please} \\ $$$$ \\ $$

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