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Question-212417




Question Number 212417 by mr W last updated on 13/Oct/24
Commented by mr W last updated on 13/Oct/24
unsolved old question 212291
$${unsolved}\:{old}\:{question}\:\mathrm{212291} \\ $$
Answered by mr W last updated on 13/Oct/24
Commented by mr W last updated on 13/Oct/24
Z=X+10  X+25=Z+10+Y=X+20+Y  ⇒Y=5  X×Y=10×25  ⇒X=50  [ABCD]=10+25+50+5=90 ✓
$${Z}={X}+\mathrm{10} \\ $$$${X}+\mathrm{25}={Z}+\mathrm{10}+{Y}={X}+\mathrm{20}+{Y} \\ $$$$\Rightarrow{Y}=\mathrm{5} \\ $$$${X}×{Y}=\mathrm{10}×\mathrm{25} \\ $$$$\Rightarrow{X}=\mathrm{50} \\ $$$$\left[{ABCD}\right]=\mathrm{10}+\mathrm{25}+\mathrm{50}+\mathrm{5}=\mathrm{90}\:\checkmark \\ $$
Commented by mr W last updated on 13/Oct/24
Commented by mr W last updated on 13/Oct/24
(B/C)=(A/D) ⇒A×C=B×D
$$\frac{{B}}{{C}}=\frac{{A}}{{D}}\:\Rightarrow{A}×{C}={B}×{D} \\ $$
Commented by hardmath last updated on 13/Oct/24
thankyou dearprofessor
$$\boldsymbol{\mathrm{t}}\mathrm{hank}\boldsymbol{\mathrm{y}}\mathrm{ou}\:\boldsymbol{\mathrm{d}}\mathrm{ear}\boldsymbol{\mathrm{p}}\mathrm{rofessor} \\ $$

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