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Q-In-AB-C-cos-A-cos-B-2cos-C-2-show-that-a-b-2c-




Question Number 212552 by mnjuly1970 last updated on 17/Oct/24
    ^(Q:)  In AB^Δ C :   cos(A) +cos(B )+ 2cos(C )= 2             show that :   a + b = 2c           ■
Q:InABCΔ:cos(A)+cos(B)+2cos(C)=2showthat:a+b=2c◼
Answered by Ghisom last updated on 17/Oct/24
C=π−(A+B) ⇒  cos A +cos B −cos (A+B) =2  c=((a+b)/2) ⇒  a^2 +b^2 +2abcos C =c^2  etc. lead to  (1) cos A =((5b−3a)/(4b)) ⇒       sin A =((√(−3(a−3b)(3a−b)))/(4b))  (2) cos B =((5a−3b)/(4a)) ⇒       sin B =((√(−3(a−3b)(3a−b)))/(4a))    (3) cos A cos B −sin A sin B=−((3a^2 −2ab+3b^2 )/(8ab))  cos (A+B) =cos A cos B −sin A sin B  inserting from above  ⇒ true
C=π(A+B)cosA+cosBcos(A+B)=2c=a+b2a2+b2+2abcosC=c2etc.leadto(1)cosA=5b3a4bsinA=3(a3b)(3ab)4b(2)cosB=5a3b4asinB=3(a3b)(3ab)4a(3)cosAcosBsinAsinB=3a22ab+3b28abcos(A+B)=cosAcosBsinAsinBinsertingfromabovetrue

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