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Question Number 212550 by mnjuly1970 last updated on 17/Oct/24
      the following equation has       no root . find the relationship     between a , b , c :      1:  c≤2      2: c >2      3: c >ab      4: c≤ ab      eq^n  :  (√( x+1+b +2(√(x+b)) )) + (√(x+1+a +2(√(x+a)))) = c
thefollowingequationhasnoroot.findtherelationshipbetweena,b,c:1:c22:c>23:c>ab4:cabeqn:x+1+b+2x+b+x+1+a+2x+a=c
Answered by Ghisom last updated on 17/Oct/24
x+1+α+2(√(x+α))=(1+(√(x+α)))^2   solving in R ⇒ (√(x+α))≥0  (√(x+a))+(√(x+b))=c−2  c−2>0 ⇒ c>2
x+1+α+2x+α=(1+x+α)2solvinginRx+α0x+a+x+b=c2c2>0c>2
Commented by mnjuly1970 last updated on 17/Oct/24

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