certificate-lim-n-0-1-n-1-n-2-x-2-e-x-3-dx-pi-2- Tinku Tara October 18, 2024 None 0 Comments FacebookTweetPin Question Number 212600 by MrGaster last updated on 18/Oct/24 certificate:limn→∞∫01n1+n2x2ex3dx=π2. Answered by Berbere last updated on 21/Oct/24 Extra \left or missing \rightExtra \left or missing \right=π2e−limn→∞∫013x2ex3tan−1(nx)dxπ2−1x⩽tan−1(x)=π2−tan−1(1x)⩽π2(π2−1nx)3x2ex3⩽3x2ex3tan−1(nx)⩽π2.3x2ex3limn→∞π2e−π2−1n∫013xex3⩽u=limn→∞∫013x2ex3tan−1(nx)⩽π2e−π2π2e−π2−1n∫013xex2dx⩽π2e−π2−1n∫013xex3⩽u⩽π2e−π2limn→∞π2e−π2−32n(e−1)⩽u⩽π2e−π2u=π2e−π2;A=π2e−u=π2 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-212602Next Next post: Question-212607 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.