Question Number 212761 by Spillover last updated on 23/Oct/24
Commented by mr W last updated on 23/Oct/24
$${AB}=\mathrm{2}×{GE}=\mathrm{8}\sqrt{\mathrm{7}} \\ $$
Answered by som(math1967) last updated on 23/Oct/24
Commented by som(math1967) last updated on 23/Oct/24
$${PQ}=\frac{\mathrm{1}}{\mathrm{2}}{AQ} \\ $$$${QR}=\frac{\mathrm{1}}{\mathrm{2}}{QB} \\ $$$${PQ}+{QR}=\frac{\mathrm{1}}{\mathrm{2}}\left({AQ}+{QB}\right) \\ $$$${PR}=\frac{\mathrm{1}}{\mathrm{2}}{AB} \\ $$$${GE}=\frac{\mathrm{1}}{\mathrm{2}}{AB} \\ $$$$\therefore{AB}=\mathrm{2}{GE}=\mathrm{2}×\mathrm{4}\sqrt{\mathrm{7}}=\mathrm{8}\sqrt{\mathrm{7}}{cm} \\ $$$${there}\:{are}\:{no}\:{use}\:{of}\:{rad}\:{of}\:{big}\:{circle} \\ $$$${or}\:{CD} \\ $$
Commented by Spillover last updated on 24/Oct/24
$${thank}\:{you} \\ $$
Answered by Spillover last updated on 24/Oct/24
