prove-lim-n-0-1-n-1-n-2-x-2-e-x-2-dx-pi-2- Tinku Tara October 31, 2024 Limits 0 Comments FacebookTweetPin Question Number 213169 by MrGaster last updated on 31/Oct/24 provelimn→∞∫01n1+n2x2ex2dx=π2. Answered by Berbere last updated on 31/Oct/24 ∫>1n1+n2x2ex2dx=[tan−1(nx)ex2]−∫012xex2tan−1(nx)dx=π2e−∫012xex2tan−1(nx)dx=πe2−∫012xex2[π2−tan−1(1nx)]dx=πe2−π2(e−1)+2∫01xex2tan−1(1nx)=π2+B∀x⩾0tan−1(x)<x⇒∫01xex2tan−1(1nx)dx⩽∫01ex2ndx⩽en⇒limn→∞B=0⇒limn→∞∫01n1+n2x2ex2dx=π2 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-213139Next Next post: we-can-find-tan120-by-tan-180-60-but-can-not-find-by-tan-90-30-why- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.