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Question-213342




Question Number 213342 by Spillover last updated on 03/Nov/24
Commented by MrGaster last updated on 03/Nov/24
                 determinant (((  ∫H_x ^(√π) dx=(H_x ^((√π)+1) /( (√π)+1))+C  )))
$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\begin{array}{|c|}{\:\:\int{H}_{{x}} ^{\sqrt{\pi}} {dx}=\frac{{H}_{{x}} ^{\sqrt{\pi}+\mathrm{1}} }{\:\sqrt{\pi}+\mathrm{1}}+{C}\:\:}\\\hline\end{array} \\ $$

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