Question Number 213436 by mr W last updated on 05/Nov/24
![](https://www.tinkutara.com/question/35435.png)
Answered by A5T last updated on 05/Nov/24
![](https://www.tinkutara.com/question/35439.png)
Commented by mr W last updated on 05/Nov/24
��
Commented by A5T last updated on 05/Nov/24
![sinθ=((15)/( (√(26^2 +15^2 ))))=((15)/( (√(901))))⇒cosθ=((26)/( (√(901)))) ⇒sin2θ=2sinθcosθ=((780)/(901)) [ABC]=15(((26×2+25×2+2x)/2))=(((26+x)(26+25)sin2θ)/2) ⇒x=27](https://www.tinkutara.com/question/Q213441.png)
Answered by mr W last updated on 05/Nov/24
![](https://www.tinkutara.com/question/35440.png)
Commented by mr W last updated on 05/Nov/24
![tan α=((15)/x) tan β=((15)/(26)) tan γ=((15)/(25)) α+β+γ=((180°)/2)=90° tan α=(1/(tan (β+γ)))=((1−tan β tan γ)/(tan β+tan γ)) ((15)/x)=((1−((15)/(26))×((15)/(25)))/(((15)/(26))+((15)/(25))))=((26×25−15^2 )/(15×(25+26)))=(5/9) ⇒x=27 A=(25+26+27)×15=1170](https://www.tinkutara.com/question/Q213444.png)