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The-two-corner-points-of-a-square-lie-on-curve-f-x-x-2-2x-3-and-the-other-two-corner-points-lie-on-curve-g-x-x-2-2x-3-It-is-known-that-the-area-of-a-square-can-be-expressed-by-p-




Question Number 213522 by efronzo1 last updated on 07/Nov/24
  The two corner points of a square     lie on curve f(x)= x^2 −2x−3 and    the other two corner points lie on    curve g(x)= −x^2 +2x+3 . It is known   that the area of a square can be     expressed by p+q(√r) , for a natural    number p,q ,r where r is not divisible    by any perfect square number other 1.   The value of p+q+r =?
Thetwocornerpointsofasquarelieoncurvef(x)=x22x3andtheothertwocornerpointslieoncurveg(x)=x2+2x+3.Itisknownthattheareaofasquarecanbeexpressedbyp+qr,foranaturalnumberp,q,rwhererisnotdivisiblebyanyperfectsquarenumberother1.Thevalueofp+q+r=?

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